Optimal. Leaf size=154 \[ \frac {e^{i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (-\frac {i d (e+f x)}{f}\right )^{-m} \Gamma \left (m+1,-\frac {i d (e+f x)}{f}\right )}{2 a d}+\frac {e^{-i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (\frac {i d (e+f x)}{f}\right )^{-m} \Gamma \left (m+1,\frac {i d (e+f x)}{f}\right )}{2 a d}+\frac {(e+f x)^{m+1}}{a f (m+1)} \]
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Rubi [A] time = 0.18, antiderivative size = 154, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {4523, 32, 3308, 2181} \[ \frac {e^{i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (-\frac {i d (e+f x)}{f}\right )^{-m} \text {Gamma}\left (m+1,-\frac {i d (e+f x)}{f}\right )}{2 a d}+\frac {e^{-i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (\frac {i d (e+f x)}{f}\right )^{-m} \text {Gamma}\left (m+1,\frac {i d (e+f x)}{f}\right )}{2 a d}+\frac {(e+f x)^{m+1}}{a f (m+1)} \]
Antiderivative was successfully verified.
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Rule 32
Rule 2181
Rule 3308
Rule 4523
Rubi steps
\begin {align*} \int \frac {(e+f x)^m \cos ^2(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac {\int (e+f x)^m \, dx}{a}-\frac {\int (e+f x)^m \sin (c+d x) \, dx}{a}\\ &=\frac {(e+f x)^{1+m}}{a f (1+m)}-\frac {i \int e^{-i (c+d x)} (e+f x)^m \, dx}{2 a}+\frac {i \int e^{i (c+d x)} (e+f x)^m \, dx}{2 a}\\ &=\frac {(e+f x)^{1+m}}{a f (1+m)}+\frac {e^{i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (-\frac {i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,-\frac {i d (e+f x)}{f}\right )}{2 a d}+\frac {e^{-i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (\frac {i d (e+f x)}{f}\right )^{-m} \Gamma \left (1+m,\frac {i d (e+f x)}{f}\right )}{2 a d}\\ \end {align*}
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Mathematica [A] time = 0.98, size = 220, normalized size = 1.43 \[ \frac {e^{i \left (c-\frac {d e}{f}\right )} (e+f x)^m \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^2 \left (\frac {d^2 (e+f x)^2}{f^2}\right )^{-m} \left (2 d (e+f x) e^{-i \left (c-\frac {d e}{f}\right )} \left (\frac {d^2 (e+f x)^2}{f^2}\right )^m+f (m+1) e^{-2 i \left (c-\frac {d e}{f}\right )} \left (-\frac {i d (e+f x)}{f}\right )^m \Gamma \left (m+1,\frac {i d (e+f x)}{f}\right )+f (m+1) \left (\frac {i d (e+f x)}{f}\right )^m \Gamma \left (m+1,-\frac {i d (e+f x)}{f}\right )\right )}{2 a d f (m+1) (\sin (c+d x)+1)} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.49, size = 130, normalized size = 0.84 \[ \frac {{\left (f m + f\right )} e^{\left (-\frac {f m \log \left (\frac {i \, d}{f}\right ) - i \, d e + i \, c f}{f}\right )} \Gamma \left (m + 1, \frac {i \, d f x + i \, d e}{f}\right ) + {\left (f m + f\right )} e^{\left (-\frac {f m \log \left (-\frac {i \, d}{f}\right ) + i \, d e - i \, c f}{f}\right )} \Gamma \left (m + 1, \frac {-i \, d f x - i \, d e}{f}\right ) + 2 \, {\left (d f x + d e\right )} {\left (f x + e\right )}^{m}}{2 \, {\left (a d f m + a d f\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (f x + e\right )}^{m} \cos \left (d x + c\right )^{2}}{a \sin \left (d x + c\right ) + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.20, size = 0, normalized size = 0.00 \[ \int \frac {\left (f x +e \right )^{m} \left (\cos ^{2}\left (d x +c \right )\right )}{a +a \sin \left (d x +c \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (f x + e\right )}^{m} \cos \left (d x + c\right )^{2}}{a \sin \left (d x + c\right ) + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\cos \left (c+d\,x\right )}^2\,{\left (e+f\,x\right )}^m}{a+a\,\sin \left (c+d\,x\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {\left (e + f x\right )^{m} \cos ^{2}{\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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